w/(w-3)-2w/(2x-1)=(w-3)/(2w^2-7w+3)

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Solution for w/(w-3)-2w/(2x-1)=(w-3)/(2w^2-7w+3) equation: 


D( x )

w-3 = 0

2*x-1 = 0

2*w^2-(7*w)+3 = 0

w-3 = 0

w-3 = 0

w-3 = 0

x naleu017Cy do R

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

2*w^2-(7*w)+3 = 0

2*w^2-(7*w)+3 = 0

2*w^2-7*w+3 = 0

2*w^2-7*w+3 = 0

x naleu017Cy do R

x belongs to the empty set

w/(w-3)-((2*w)/(2*x-1)) = (w-3)/(2*w^2-(7*w)+3)

x belongs to the empty set

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